フィルターのクリア

how can I do this fast addition and multiplication?

1 回表示 (過去 30 日間)
Kate
Kate 2014 年 8 月 6 日
編集済み: Kate 2014 年 8 月 6 日
Hi all,
I am transforming some data using an equation that involves a multiplication and addition. (Please see line 20 in the full code below this post., i.e. the following line:
newdata1 = (((R)*X1_full(:,i))+ T)';
In this example, I only have 4 data points (i.e. in the 'X1_full' variable). So speed is not a problem using the FOR loop. However, my actual dataset is very large (2 million data points). Any suggestion to improve the speed will be helpful.
cheers. K.
clc;clear all;close all
% input data to transform
X1_full = [1 2 3 5;
45 8 7 95;
12 78 98 3]
% R and T are transform params
T = [292.213040777858;78.1087497964877;865.7398878749]
R=[0.999998463087434,8.08983068375718e-05,-0.00175136467802407;
-8.44379283493625e-05,0.999997954040306,-0.00202108521267277;
0.00175119759243091,0.00202122998804671,0.999996423961770;]
% Loop through all data and transform
for i = 1:size(X1_full,2)
% Formula to transform the input data
newdata1 = (((R)*X1_full(:,i))+ T)';
Savenewdata1(i,:) = newdata1
end

採用された回答

Michael Haderlein
Michael Haderlein 2014 年 8 月 6 日
Savenewdata1=bsxfun(@plus,(R*X1_full),T)';
can replace your loop and should be faster than your solution.
  1 件のコメント
Kate
Kate 2014 年 8 月 6 日
編集済み: Kate 2014 年 8 月 6 日
thank you Michael.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeLogical についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by