matrix multiplication and root finding

1 回表示 (過去 30 日間)
shiv gaur
shiv gaur 2021 年 9 月 25 日
コメント済み: shiv gaur 2024 年 12 月 14 日
Mj=[cos (kj hj) i*sin(kj hj) /kj ; i*kj*sin(kj hj) cos (kj hj) ];
kj=sqrt(nj2*k02-x2);
Take n1=1.521;n2=2.66;k0=1;h1=1.5e-6;h2=1e-6
We take M=M1*M2;
Where M=( m11 m12;m21 m22) as usual in
Matrix;
How to multiply this matrix for M find the multiplication of matrix and find the value of
x;
and solve the eq
ns=1.512;
nc=1.2-i7;
gs=x2-ns2k02;
gc= x2-ns2k02;
f(x)=igsm11+gcm22)-m21+gsgcm12;
and solve the eq and value of x

採用された回答

Vidhi Agarwal
Vidhi Agarwal 2024 年 12 月 4 日
To solve the issue follow the given below steps:
  • Define the matrices.
  • Compute the matrix multiplication.
  • Formulate the function.
  • Solve the equation.
Modified code for the same is given below:
% Given values
n1 = 1.521;
n2 = 2.66;
k0 = 1;
h1 = 1.5e-6;
h2 = 1e-6;
ns = 1.512;
nc = 1.2 - 1i*7;
% Define symbolic variable for x
syms x
% Calculate k1 and k2
k1 = sqrt(n1^2 * k0^2 - x^2);
k2 = sqrt(n2^2 * k0^2 - x^2);
% Define M1 and M2 matrices
M1 = [cos(k1 * h1), 1i * sin(k1 * h1) / k1;
1i * k1 * sin(k1 * h1), cos(k1 * h1)];
M2 = [cos(k2 * h2), 1i * sin(k2 * h2) / k2;
1i * k2 * sin(k2 * h2), cos(k2 * h2)];
% Multiply matrices to get M
M = M1 * M2;
% Extract elements from M
m11 = M(1,1);
m12 = M(1,2);
m21 = M(2,1);
m22 = M(2,2);
% Define gs and gc
gs = x^2 - ns^2 * k0^2;
gc = x^2 - nc^2 * k0^2;
% Define the function f(x)
f = 1i * (gs * m11 + gc * m22) - m21 + gs * gc * m12;
% Use vpasolve for numerical solution
x_solution = vpasolve(f == 0, x);
% Display the solutions
disp('Numerical solutions for x:')
disp(x_solution)
For better understanding of basic matrix operation in MATLAB refer to the documentation https://www.mathworks.com/help/matlab/math/basic-matrix-operations.html.
Hope this helps!
  2 件のコメント
shiv gaur
shiv gaur 2024 年 12 月 14 日
thanks for answer.what will be change in program if we varying h2 from 1e-3 to 1e-6 pl provide the solution
shiv gaur
shiv gaur 2024 年 12 月 14 日
plot h2(x axis) vs x(real or x imaginary)

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeNumeric Solvers についてさらに検索

製品


リリース

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by