How to find real and complex roots for a nonlinear equation

Hi everyone,

I have to solve this eqution numerically:

the only variable is H and it tipically gives two complex roots and one real root, I've read that fzero is not suitable in this case, could anyone give mi any tips please?

Thank you

Answer 1

[Viranch Patel]

For simplicity I have taken a simple function which has complex roots.

syms H
eq=H^2 + 1;
solve(eq==0,H)

You can specify your equation in H like this and this should give you the roots correctly.

[Marco Dellacasa]

Warning: Unable to solve symbolically. Returning a numeric solution using vpasolve. 
> In sym/solve (line 304)
In prova_Irvine (line 15) 
 
ans =
 
-8530666.6665264117623777679822889
 
>> 

Unfortunately it didn't work, I know a priori that usually this equation has in total 3 roots: 2 complex and 1 real, maybe the problem is that I have both real and complex roots to find instead only real or only complex roots?