separate strings that are inside a cell
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Hey so I got a cell that is 12000x1 and inside this cell I got some strings that are 2x1 or 3x1. I want to delete this string but get the messages from there and put them inside the cell. Is there any function that let me do this?
4 件のコメント
Jan
2021 年 9 月 17 日
Yes, I see it. What do you want todo with these strings? Remove them or replace them? In the latter case: by what?
採用された回答
Jan
2021 年 9 月 18 日
編集済み: Jan
2021 年 9 月 18 日
Your description is not clear yet. I dare to guess:
% Input (thanks Adam):
C = {"sdfsd"; "dare"; ["abs";"ses"]; "erwe"; "serwe"; ...
["444";"wer"]; "adrwed"; ["ee";"vse";"xxx"]; "sered"}
% Wanted output:
C = {"sdfsd"; "dare"; "abs";"ses"; "erwe"; "serwe"; ...
"444"; "wer"; "adrwed"; "ee"; "vse"; "xxx"; "sered"}
% Solution:
D = cellstr(cat(1, C{:}))
その他の回答 (1 件)
Adam Danz
2021 年 9 月 17 日
編集済み: Adam Danz
2021 年 9 月 17 日
If your goal is to simply be able to read those lines, use cellfun to identify elements of cell array "C" that have more than one row of strings and then use cellfun again to transpose those rows.
Create demo data - you can see that there are 3 elements of C that are 2x1 or 3x1 string arrays
C = {"sdfsd"; "dare"; ["abs";"ses"]; "erwe"; "serwe"; ...
["444";"wer"]; "adrwed"; ["ee";"vse";"xxx"]; "sered"}
Transpose mutli-rows
[nRows, ~] = cellfun(@size,C);
isMultiRow = nRows>1;
C(isMultiRow) = cellfun(@(a) {a'}, C(isMultiRow))
If you'd like to join those strings into 1, replace the line above with this line.
C(isMultiRow) = cellfun(@(a) {strjoin(a,' ')}, C(isMultiRow))
10 件のコメント
Adam Danz
2021 年 9 月 18 日
@vicente Noguer, no problem, I agree with Jan. Providing sample of inputs (as you provided) and samples of expected outputs goes a long way.
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