Extracting rows in row-wise manner. How to do this?

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S Priya
S Priya 2021 年 9 月 16 日
回答済み: Image Analyst 2021 年 9 月 16 日
Suppose,a matrix A, A=[1 2 3 4; 1 0 2 8; 1 2 3 6....]
Size(A)=100 4
And I want to extract each row in a row-wise manner (ie.row1,then row2, row3....)and then place it in seperate B matrix where 1 row will be used at a time.
How to do this?
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per isakson
per isakson 2021 年 9 月 16 日
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回答 (2 件)

KSSV
KSSV 2021 年 9 月 16 日
Question sounds very silly. You can use a lloop.
A = rand(100,4) ;
B = zeros(100,4) ;
for i = 1:100
thisrow = A(i,:) ;
B(i,:) = thisrow ;
end

Image Analyst
Image Analyst 2021 年 9 月 16 日
Try this:
[rows, columns] = size(A);
for row = 1 : rows
% Extract a row of A (all columns of it) into a new row vector, B.
B = A(row, :)
% Now use B in whatever way you want. It will get overwritten on each iteration, but that shouldn't matter.
end

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