How to create a new matrix with a for loop?

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Mert Dogan
Mert Dogan 2021 年 9 月 15 日
コメント済み: Mert Dogan 2021 年 9 月 15 日
Hello friends,
I am a newbie. I have problem.
I have 20 (1x100) different named vectors. I want to combine these vectors to create a 20x100 matrix with a for loop.
There are the examples of vectors.
namelist=["First","B","New"]
namelist = 1×3 string array
"First" "B" "New"
First = [1:100]
First = 1×100
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
B = [1:2:200]
B = 1×100
1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49 51 53 55 57 59
New = [4:4:400]
New = 1×100
4 8 12 16 20 24 28 32 36 40 44 48 52 56 60 64 68 72 76 80 84 88 92 96 100 104 108 112 116 120
I want to create a new database(20x100) with "First, B , New" vectors with a for loop.
for i = 1: length(namelist)
new_database(i,1:end) = namelist{i}
end
The end operator must be used within an array index expression.
But, when I want to try this I saw "The end operator must be used within an array index expression." error.
I know I can do same thing with this code
new_database= [First;B;New]
but i want to do this with a for loop.
Would you help me how can fix this error? or Would you explain me how can do this?

採用された回答

KSSV
KSSV 2021 年 9 月 15 日
You should not create individual arrays like that. You should proceed something like this
iwant = zeros(3,100) ;
iwant(i,:) = 1:1:100 ;
iwant(2,:) = 2:2:200 ;
iwant(3,:) = 4:4:400 ;
  1 件のコメント
Mert Dogan
Mert Dogan 2021 年 9 月 15 日
Thanks for your answer.
I had already created individual arrays like that. I must to process them.

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