operations on two different matrices

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Mohamed Hajjaj
Mohamed Hajjaj 2021 年 9 月 14 日
コメント済み: Mohamed Hajjaj 2021 年 9 月 16 日
I need to replace the first row from a matrix A(m.m) by first row from another matrix B(n.n) with different size?

採用された回答

Walter Roberson
Walter Roberson 2021 年 9 月 16 日
D0 j=1,8
A(1, j)=D(2,j+1)
end do
Acol = size(A,2);
A(1,:) = D(2,2:Acol+1);
vec = DD1(1,:);
A1(idx,:) = repmat(vec,numel(idx),1);
Acol = size(A,2);
vec = DD1(1,1:Acol);
A1(idx,:) = repmat(vec, numel(idx), 1);
  1 件のコメント
Mohamed Hajjaj
Mohamed Hajjaj 2021 年 9 月 16 日
Yes, it works. Thank you very much for your help.

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その他の回答 (1 件)

the cyclist
the cyclist 2021 年 9 月 14 日
編集済み: the cyclist 2021 年 9 月 15 日
Suppose ...
m = 3;
n = 4;
A = magic(m)
A = 3×3
8 1 6 3 5 7 4 9 2
B = magic(n)
B = 4×4
16 2 3 13 5 11 10 8 9 7 6 12 4 14 15 1
The first row of A is a 1x3 row vector, and the first row of B is a 1x4 row vector. What do you want the output to be? Also, what if m had been greater than n?
  6 件のコメント
the cyclist
the cyclist 2021 年 9 月 15 日
Sorry, but your last two comments are just confusing to me.
You did not respond to my questions. What are the results for Case 1, Case 2, etc?
I don't know Fortran anymore, so cannot interpret that.
Why are you suddenly introducing new variables (D, DD1, idx)? Your original question seemed very simple, about filling in the first row of a matrix A, from the first row of a matrix B. It seems to be getting more and more complicated with every comment.
Mohamed Hajjaj
Mohamed Hajjaj 2021 年 9 月 16 日
The first case is the nearest one to my problem.The symbols D, DD1, ...are matrices, but I'm sorry about any confusion. Would you please help me for the first case?

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