2nd order system in Simulink

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Angelica Belo
Angelica Belo 2021 年 9 月 5 日
編集済み: Gagan Baishya 2021 年 9 月 15 日
I was tasked to construct the following 2nd order system in simulink:
y'' + 5y' + 6 = 0; y(0) = 0, y'(0) = 1
I have the following so far:
I'm not sure where and how I can input the y(0) = 0, y'(0) = 1 part.
I was wondering if I'm missing something or if this is correct already. Thank you!
  1 件のコメント
Paul
Paul 2021 年 9 月 5 日
Are you sure that differential equation shouldn't be: y'' + 5y' + 6y = 0 ?

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回答 (1 件)

Gagan Baishya
Gagan Baishya 2021 年 9 月 15 日
編集済み: Gagan Baishya 2021 年 9 月 15 日
Hi,
You are missing one more integrator block. Also you can specify the initial condition by simply double clicking both the integrator blocks and setting the initial condition to 0 & 1.
To understand more about drawing ODEs in Simulink, please follow the link below: https://blogs.mathworks.com/simulink/2008/05/23/how-to-draw-odes-in-simulink/

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