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How to find the closed form solution of the natural and forced response of 2sin(3t) - 4x with x(0) = 0

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Angelica Belo
Angelica Belo 2021 年 9 月 3 日
コメント済み: Angelica Belo 2021 年 9 月 3 日
So far I have used dsolve and have the following code:
syms x(t)
eqn = diff(x,t) == 2*sin(3*t)-4*x;
S = dsolve(eqn)
with the result as
S =
C1*exp(-4*t) - (2*cos(3*t + atan(4/3)))/5
However seeing the result, I am not very sure if I am doing this correctly. Any help would be greatly appreciated. Thanks!

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John D'Errico
John D'Errico 2021 年 9 月 3 日
編集済み: John D'Errico 2021 年 9 月 3 日
Why do you think it is not correct? Would dsolve lie? That dsolve code must be pretty darn tricky.
In fact, you have not used dsolve completely properly, because you never supplied the initial condition. You could have done so after the fact though, by solving for C in your solution such that the initial condition applies.
syms x(t)
eqn = diff(x) == 2*sin(3*t) - 4*x;
xsol = dsolve(eqn,x(0) == 0)
xsol = 
Is that the solution? Does it satisfy the initial condition?
subs(xsol,t,0)
ans = 
0
Clearly it satisfies the initial condition.
simplify(subs(eqn,x,xsol))
ans(t) = 
symtrue
It does satisfy the ODE.
  1 件のコメント
Angelica Belo
Angelica Belo 2021 年 9 月 3 日
You are an amazing teacher. Thank you for taking the time to answer my question in detail :)

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