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Comparing the data and Pairing a data - Problem occurs - Needed help

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Vasu dev
Vasu dev 2021 年 9 月 3 日
コメント済み: Sreedhar Arumugam 2021 年 9 月 8 日
Hello all, inorder to do MRC i need to do a pairing process as per my project
Consider some vectors
a1 =[1 2 3 4 5 6 7 8]'; b1= [3 3 2 3 2 3 3 2]'; c1=zeros[8,1];
I need to check b1(1)==3 if it is 3 then allocate a1(1) value in c1(1),
then i need to check b1(2)==3 if it is 3 then allocate a1(1) (SAME VALUE OF a1(1)) value in c1(2).
Now c1(1) & c1(2) = a1(1) ie. 1
Like this where ever 3 comes i need to take 3 as a pair and respective values to be repeated twice.
Then I need to check b1(3)==3 if it is not equal to 3 then allocate a1(2) (NEXT VALUE OF a1 vector) value in c1(3)
Now c1(3)= a1(2) ie.2
Then i need to check b1(4)==3 if it is equal then allocate a1(3) (NEXT VALUE OF a1 vector) value in c1(4)
Now c1(4)=a1(3) ie.3
Then i need to check b1(5)==3 if it is not equal to 3 then allocate a1(4) (NEXT VALUE OF a1 vector) value in c1(5)
Now c1(5)=a1(4) ie.4
Then i need to check b1(6)==3 if it is equal then allocate a1(3) (SAME VALUE OF a1 vector which is not paired before) value in c1(6)
Now c1(6)=a1(3) ie.3
c1(4) & c1(6)=a1(3) ie. 3 should be allocated
this is the code i have written
for i=1:2:8
for j=i:i+1
if b1(j)==3
c1(j)=a1(i);
else
c1(j)=a1(i);
end
end
end
MY EXPECTED OUTPUT IS c1=[1 1 2 3 4 3 5 6]'
The output I am getting is c1 =[ 1 1 3 3 5 5 7 7]'
NOTE: In my program vector b1 is randomised with the values 2,3 so i cannot predict the position.
Kindly suggest a solution to my problem, Thanks in advance.
  1 件のコメント
Sreedhar Arumugam
Sreedhar Arumugam 2021 年 9 月 8 日
Could you please provide another sample test case?

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