how to form a matrix with non-numeral entries and then set conditions for each case

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R@SH
R@SH 2021 年 9 月 2 日
コメント済み: R@SH 2021 年 9 月 2 日
I want to form a 1*n matrix which have enries of only two cases (like h and c) which are non-numeral as below:
A[1,n]={'h','c'}
A[1,n]=[h c h h h ......c]
and then set a condition if the case is "h" or "c", like
for i=1:n
If A[1,i]==h
Statement
end
However this way of forming code is not correct
I would really appreciate if I cn have your support.
NOH=3;
NOC=2;
Tetta=70*pi/180
for i=1:NOC+NOH
A(1,i)={'h','c'};
A(1,i)=input ('Please enter orientation of ith layer:');
if A(1,i)==h
t_h(i)=0.36
else if A(1,i)==c
t_c(i)=0.85
end
end
end

採用された回答

Awais Saeed
Awais Saeed 2021 年 9 月 2 日
I have made some corrections in your code
clc;clear all;close all
NOH=3;
NOC=2;
Tetta=70*pi/180
A = {}
for i=1:NOC+NOH
i
A(1,i) = input ('Please enter orientation of ith layer:');
if strcmp(A(1,i), 'h') % use strcmp to compare string
% Do not use == for string comparison
t_h(i) = 0.36
elseif strcmp(A(1,i), 'c')
t_c(i) = 0.85
end
end
  4 件のコメント
R@SH
R@SH 2021 年 9 月 2 日
I sincerely appreciate your both (awais and walter) support. now it works

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