Decrementing step for loop I matlab

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Dennis M
Dennis M 2021 年 8 月 24 日
コメント済み: Dennis M 2021 年 8 月 24 日
y = zeros(1,12);
for i = 1:12
y(i+1) = y(i) + ((5 - (4/50)*y(i)));
end
y
x = zeros(1,10);
for i = 10:-1:2
x(i-1) = x(i) + ((5 + (4/50)*x(i)));
end
x
Good Day,
May I ask how can I insert the start and stop variable on above code? for example I want to start in 17 to 30 or 15 to 2 with decrementing step.
Thanks and Regards,
Dennis

回答 (1 件)

Awais Saeed
Awais Saeed 2021 年 8 月 24 日
編集済み: Awais Saeed 2021 年 8 月 24 日
% start, step, and end points
starty = 1;
endy = 12;
startx = 10;
endx = 2;
decrement = -1;
y = zeros(1,12);
for i = starty:endy
y(i+1) = y(i) + ((5 - (4/50)*y(i)));
end
y
x = zeros(1,10);
for i = startx:decrement:endx
x(i-1) = x(i) + ((5 + (4/50)*x(i)));
end
x
  3 件のコメント
Dennis M
Dennis M 2021 年 8 月 24 日

<<

>> There was error when I change the variables, I have to change also the y = zeros(1,12); defend on the length. I want a loop that the output is like this (10 20 29 38 47 56 65 and so on) and (80 70 61 53 46 40 35 and so on) same in negative (-10 -20 -29 -38 -47 -56 -65 and so on) and (-80 -70 -61 -53 -46 -40 -35 and so on)

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