How to make a new table from two different table with common value?

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jeon
jeon 2021 年 8 月 23 日
コメント済み: Eric Sofen 2021 年 8 月 23 日
Hello. I have 4800960x1 table T1, 77449x1 table T2.
T1 and T2 is like
column 1 column 2
datetime value
I want to make a new table with 3 columns(common datetime of T1 and T2, value of T1, value of T2)
So far, I made 77209x1 datetime C which is the common datetime of T1 and T2.
I tried to make a new 77209x3 table which has 3 columns(datetime of C, values from T1, values from T2).
for example:
C
2010-01-01 01:00:00
2010-01-01 02:00:00
2010-01-01 03:00:00
2010-01-01 04:00:00
T1
2010-01-01 01:00:00 10
2010-01-01 02:00:00 11
2010-01-01 03:00:00 12
2010-01-01 04:00:00 13
2010-01-01 05:00:00 14
2010-01-01 06:00:00 15
2010-01-01 07:00:00 16
2010-01-01 08:00:00 17
T2
2010-01-01 01:00:00 0
2010-01-01 02:00:00 1
2010-01-01 03:00:00 2
2010-01-01 04:00:00 3
result:
2010-01-01 01:00:00 10 0
2010-01-01 02:00:00 11 1
2010-01-01 03:00:00 12 2
2010-01-01 04:00:00 13 3
I tried to use innerjoin, but it didn't work because C was not a table.
How can I get the results I want?

回答 (3 件)

KSSV
KSSV 2021 年 8 月 23 日
Let T1 and T2 be your tables having two columnn each.
idx = ismember(T.(1),T.(2)) ;
T1 = T1(idx,:) ;
T1.(3) = T2.(2) ;

Wan Ji
Wan Ji 2021 年 8 月 23 日
編集済み: Wan Ji 2021 年 8 月 23 日
result has the same row number as T1 or T2?
result = table(C,'variablenames',{'datetime'});
result.value1 = T1.value(1:(size(result,1)),1);
result.value2 = T2.value(1:(size(result,1)),1);

Eric Sofen
Eric Sofen 2021 年 8 月 23 日
You should be able to use innerjoin on T1 and T2 - no need for C. The innerjoin function calculates the equivalent of C as an intermediate step. I think @KSSV's answer will run into trouble if there are times in T2 that aren't in T1, because it's assuming that T1(idx,:) is the same size as T2.
  2 件のコメント
KSSV
KSSV 2021 年 8 月 23 日
ismember finds the common dates in T1 and T2. idx will be logical.
Eric Sofen
Eric Sofen 2021 年 8 月 23 日
Consider a modified version of @jeon's original sample data.
T1
2010-01-01 01:00:00 10
2010-01-01 03:00:00 12
2010-01-01 05:00:00 14
2010-01-01 07:00:00 16
2010-01-01 09:00:00 17
T2
2010-01-01 01:00:00 0
2010-01-01 02:00:00 1
2010-01-01 03:00:00 2
2010-01-01 04:00:00 3
idx = ismember(T1.(1),T2.(1))
idx =
5×1 logical array
1
1
0
0
0
T1 = T1(idx,:); % table with 2 rows.
T2.(3) = T2.(2) % Error because T2.(2) has 4 rows.
To assign to or create a variable in a table, the number of rows must match the height of the table.

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