# How can I write a for loop to do algebra over multiple arrays?

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Havi Tripathi 2021 年 8 月 20 日
コメント済み: Havi Tripathi 2021 年 8 月 20 日
I have 4 1x28 arrays.
I want to solve an equation for time, also linearly spaced as 1x28, for each value in this row.
a = linspace(3,28,28);
b = linspace(4,28,28);
c = linspace(5,28,28);
d = linspace(6,28,28);
time = linspace(1,28,28);
for i = 1:28:
value = a.*time ./ (c+d)
end
So, in the end, value should be a 28x28 array right. The first column of value, for example, should be value evaluated at time 1.
As it goes downward in column 1, it should be evaluated at time 2, etc till 28.
I'm not sure how to actually implement this. When I am doing it regularly, I get back a 1x28 array from value.
Does anyone know the approach or solution I am looking for?

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### 採用された回答

Wan Ji 2021 年 8 月 20 日
Do loop with indices of t:
a = linspace(3,28,28)';
b = linspace(4,28,28)';
c = linspace(5,28,28)';
d = linspace(6,28,28)';
time = linspace(1,28,28);
value = zeros(28,28);
for i = 1:28
value(:,i) = a.*time(i)./ (c+d);
end
And then the value becomes 28*28 as you want.
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Havi Tripathi 2021 年 8 月 20 日
Thanks for the quick help! I understand indexing better now.

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### その他の回答 (1 件)

Simon Chan 2021 年 8 月 20 日
Try this:
A = arrayfun(@(x) x.*time./(c+d), a, 'UniformOutput', false)
result = cell2mat(A')

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R2020b

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