How to remove LQR error ?
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I am using LQR command in matlab for getting gain of matrix
A=[-1 1;0 2];
B=[1;0];
Q=[1 0;0 1];
R=[1];
k=lqr(A,B,Q,R)
I get error Like this
Error using lqr
The "lqr" command failed to stabilize the plant or find an optimal feedback gain. To remedy
this problem:
- Make sure that all unstable poles of A are controllable through B (use MINREAL to check)
- Modify the weights Q and R to make [Q N;N' R] positive definite (use EIG to check positivity).
Is there any way to remove that error without using "minreal "command because if I use this then I am left with just 1 state(but I am using 5 states in my problem).I am changing my weights(Q and R by hit and trial method) as well to solve this problem but still fails.I will be very grateful to you if you help me out in this regard. is there any way of calculating Q and R weights for my matrix?
Can anyone help me in this regard.
1 件のコメント
回答 (2 件)
Azzi Abdelmalek
2014 年 7 月 28 日
Your model does not have 5 states (juste 2 states),one of them is not controllable. then you can't calculate the gain k by lqr method. The only way is to use minreal.
Muhammad Ali
2014 年 11 月 2 日
"Minreal" command should solve your problem, because any of your state makes the plant uncontrollable.
2 件のコメント
Bilal sadiq
2018 年 8 月 10 日
編集済み: Walter Roberson
2018 年 8 月 11 日
sara is clearly asking that she/he has 5 states out of it only 1 state is controllable and obviously if she/he use minreal command it will return only 1 state then how one can apply lqr ?(or some other method) say for example
x1=translational displacement
x2=translational velocity
x3=angular position
x4=angular velocity
x5=actuator output
and suppose out of all these 5 state (after using minreal) we get only 1 state (say for example x2) then what should we do??? while our main objective was to control x3
hope you get what i am and sara suppose to ask
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