Interpolation of unequally spaced data

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dEEPAK MAT
dEEPAK MAT 2014 年 7 月 15 日
コメント済み: Image Analyst 2014 年 7 月 15 日
I have a small set of (x,y) data points which are not evenly spaced. I want to interpolate the data for some analysis work.With very few points I am unable to work out.I cant use interp1 for the data is not evenly spaced.ANY SUGGESTIONS ?
3425.0 12.5 825.0 25 200 37.5 75 50 25 62.5 12.5 75
  2 件のコメント
Image Analyst
Image Analyst 2014 年 7 月 15 日
Please supply the x locations, and the y values of your input data. Then supply us the x locations of the places where you want your estimated output y values.
John D'Errico
John D'Errico 2014 年 7 月 15 日
It is simply NOT true that you cannot use interp1. READ THE HELP.

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Star Strider
Star Strider 2014 年 7 月 15 日
Your data do not have to be evenly spaced to use interp1.
For example:
x = sort(unique(randi(50,1,10)));
y = randi(10,1,length(x));
xi = linspace(0,max(x),15);
yi = interp1(x,y,xi,'linear');
figure(1)
plot(x,y,'-*b')
hold on
plot(xi,yi,'pr')
hold off
grid
legend('Original','Interpolated')
  1 件のコメント
Image Analyst
Image Analyst 2014 年 7 月 15 日
It's not clear, but his xi might also be randomly located (that's why I asked), but your code should also work with
xi = sort(unique(randi(50,1,10)));
just as well, since, like John said, there's no reason interp1 won't work with randomly located data.

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