How to find repeated array in a matrix

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Moe
Moe 2014 年 7 月 9 日
回答済み: Sara 2014 年 7 月 9 日
Hello everyone,
Suppose matrix a is like:
a=[1;2;2;3;3;4;5;6;6;7;7;7;8];
and matrix b:
b=[2;7;1;3;2];
Then, I want matrix c to be like:
c = [2;3;10,11,12,1,4,5,2,3]
Matrix c is found an array of matrix b in matrix a, If it finds more than one, then it will write both or more row numbers in the matrix c

採用された回答

Sara
Sara 2014 年 7 月 9 日
d = [];
for i = 1:numel(b)
d = [d;find(a==b(i))];
end

その他の回答 (1 件)

Azzi Abdelmalek
Azzi Abdelmalek 2014 年 7 月 9 日
編集済み: Azzi Abdelmalek 2014 年 7 月 9 日
You can use ismember and find function

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