replace numeric char within a column

Hey,
I would like to replace numbers (-999) as char with a 0 for all -999 in a specific column.
Thanks already!

 採用された回答

Titus Edelhofer
Titus Edelhofer 2014 年 7 月 6 日

0 投票

Hi,
it sounds as if you have a cell array of strings. In this case
allDatabySubj(strcmp(allDatabySubj, '-999)) = {0};
should do the trick.
Titus

1 件のコメント

Image Analyst
Image Analyst 2014 年 7 月 6 日
julro's "Answer" moved here since it's not an ANswer/solution to the original question:
Thanks a lot! That was the trick:).

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その他の回答 (1 件)

dpb
dpb 2014 年 7 月 6 日

0 投票

x(x(:,colID)==-999,colID)=0;
for your specific column in colID

3 件のコメント

Image Analyst
Image Analyst 2014 年 7 月 6 日
That's kind of what I was thinking but I could never figure out what the "numeric char" or "as char" part meant. I didn't know if the array was numeric, character (but with numbers as the characters), or possibly even a cell array.
dpb
dpb 2014 年 7 月 6 日
It doesn't make any sense and I don't know what was intended by it either but I am guessing it is just poor grammar from non-English native tongue poster...
Image Analyst
Image Analyst 2014 年 7 月 6 日
julro's "Answer" moved here since it's not an ANswer/solution to the original question:
Thanks! Char means character, sorry. I am getting the following error message:
>> allDatabySubj(allDatabySubj(:,6)==-999,6)=0; ??? Undefined function or method 'eq' for input arguments of type 'cell'.

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