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Convert string of hex to array of dec

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John Ramshur
John Ramshur 2011 年 8 月 17 日
I need to convert a string of hexidecimal numbers to an array of dec numbers. The string can potentially contain incomplete hex numbers at the beginning and end of the string. See examples below. I'm trying to use this in a data acquisition setup...so execution time could be a factor.
Input String Examples ('/r' = carriage returns:
s1 = '0001h/r0002h/r0003h/r';
s2 = '4h/r0001h/r0002h/r0003h/r00';
Output Desired:
a1 = [1,2,3]
a2 = [1,2,3]

採用された回答

Fangjun Jiang
Fangjun Jiang 2011 年 8 月 17 日
s1 = '0001h/r0002h/r0003h/r';
s1 = '4h/r0001h/r0002h/r0003h/r00';
str=regexp(s1,'h/r','split');
Ind=cellfun(@length,str);
str=str(Ind==4);
num=hex2dec(str);
  2 件のコメント
John Ramshur
John Ramshur 2011 年 8 月 17 日
Worked perfectly. Thanks.
Jan
Jan 2011 年 8 月 17 日
cellfun('prodofsize', str) is faster than cellfun(@length, str).

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その他の回答 (1 件)

Jan
Jan 2011 年 8 月 17 日
A simpler method, which is substantially faster:
s1 = '0001h/r0002h/r0003h/r';
a1 = sscanf(a, '%xh/r')
But this does not reject the 4 of the string '4h/r0001h/r0002h/r0003h/r00'!
If you mean \r instead /r:
s1 = sprintf('0001h\r0002h\r0003h\r');
a1 = sscanf(a, '%xh')

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