compute event rate and plot histogram

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Chiranjibi
Chiranjibi 2014 年 6 月 11 日
コメント済み: dpb 2014 年 6 月 11 日
I have 606,774(1st row means event no.1)events and 11 column data among them 9th column is the 64-bit absolute time of trigger in unix time(accurate to microsecond), I need help to compute events rate by using time stamps and make plot of event rate using mtlab. The time stamps for only 2 event is like,
1388557138250759
1388557138255312

回答 (2 件)

dpb
dpb 2014 年 6 月 11 日
W/o a lot more effort, you'll lose some precision w/ Matlab datenum but for human consumption it may be sufficient.
>> tun=[1388557138250759
1388557138255312];
>> datestr(tun/86400/1000/1000 + datenum(1970,1,1),'ddmmmyyyy hh:MM:ss.fff')
ans =
01Jan2014 06:18:58.251
01Jan2014 06:18:58.255
>> diff(tun)
ans =
4553
>>
Gives the delta-t in microseconds for a sampled timeseries which you can scale as desired.
  2 件のコメント
Chiranjibi
Chiranjibi 2014 年 6 月 11 日
Thanks, but I have 606,774 events each events has different time. Above two time stamp is only for two events. So can you please help me to calculate event rate for all events.
dpb
dpb 2014 年 6 月 11 日
diff(t)
where t is your input column vector.

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José-Luis
José-Luis 2014 年 6 月 11 日
If your want to get Matlab serial date number and you don't care about leap seconds, then you could do:
tun=int64([1388557138250759
1388557138255312]);
epoch = datenum(1970,1,1);
numDays = double(tun ./ int64(86400 * 10^6));
remainder = double(mod(tun , int64(86400*10^6))) ./ (10^6*86400);
datevec(epoch + numDays + remainder )
  8 件のコメント
Chiranjibi
Chiranjibi 2014 年 6 月 11 日
I have no idea, that's why I'm asking you. Although I got only 6 column from above code.
José-Luis
José-Luis 2014 年 6 月 11 日
Yes, but what is the formula for it? What do you want? How many times a given time stamp occurs? How do you define when two events are equal? You need that to calculate a rate.

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