subtraction and multiplication of two arrays

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Bathrinath
Bathrinath 2014 年 6 月 11 日
コメント済み: Bathrinath 2014 年 6 月 11 日
t=[19;25;29;69];T=[19;25;29;69]; i have to do the subtraction and multiplication operation using A=0.3*(t-T) to get 4X4 matrix. It is 4X4 matrix in the first column T=19 is constant similarly second T=25 is constant.third column T=29 is constant and in fourth column T=69 is constant. By using A i will get the result. my answer has to be A=[0,-0.54,-3,-15;1.8,0,-1.2,-13.2;3,1.2,0,-12;15,13.2,12,0]; Initially A will be zeros(length(t),length(T)). Suggest some points

採用された回答

Roger Stafford
Roger Stafford 2014 年 6 月 11 日
A = 0.3*bsxfun(@minus,t,T');
This gives the result you have specified except for the -0.54 at (1,2). I think that may be an error on your part.
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Bathrinath
Bathrinath 2014 年 6 月 11 日
Thank you very much sir. " I don't know how you people are doing programming like this!".Congrats sir.

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その他の回答 (1 件)

pietro
pietro 2014 年 6 月 11 日
As you did:
A=0.3*(t-T)
but in your example t and T are equal, so the result is an array full of zeros
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Bathrinath
Bathrinath 2014 年 6 月 11 日
It is 4X4 matrix in the first column T=19 is constant similarly second T=25 is constant.third column T=29 is constant and in fourth column T=69 is constant. By using A i will get the result.

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