my matrix is not square, although i think it is?
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I have set the following least squares method up quickly. I know i am using a nonlinear technique to solve a linear problem, however i just wanted to get it working, before i choose a linear method but aparently my matrices are not square:
i = [1 2 3 4 5];
ti = [2 5 7 11 14];
Estimates3=fminsearch(@functionnumbers,1,options,T0,theta_f);
and the function code
function fnumbers = functionnumbers(params3,i,ti)
k = params3;
v0 = 1 + (k/2)*ti(1)^2/ti(1)
fnumbers = sum(ti.^2*(i/ti-(v0-(k/2)*ti))^2);
cheers
3 件のコメント
採用された回答
Walter Roberson
2011 年 8 月 8 日
fminsearch() accepts at most 3 inputs, and the function passed to it must accept a single input. See http://www.mathworks.com/help/techdoc/ref/fminsearch.html
5 件のコメント
Walter Roberson
2011 年 8 月 9 日
Are you truly wanting to do a _matrix division_ between i and ti ?? If not then you should be using ./ instead of /
Are you truly wanting to do a matrix multiplication between ti.^2 and the rest of the expression? If not, then you should be using .* instead of *
その他の回答 (1 件)
Alex
2011 年 8 月 9 日
2 件のコメント
Walter Roberson
2011 年 8 月 9 日
In the original equation you had "i" divided by "ti", but in the new equations that division appears to have vanished. It does not appear to me that your old and new equations are equivalent, but it could be that I missed something.
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