Loop for words vector

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Dmytro
Dmytro 2014 年 5 月 30 日
コメント済み: Yusef Ghazwan 2020 年 6 月 16 日
Hallo everyone. I have a question. Is it possible to use a loop to create vector of words depending on the number.
As input I have a number, which can be changed according to any wish. And as a result i wont to get a row of words %input Number=10
C = cell(1,Number)
for i=1:Number
C(1,i)={'portfolio' *i* };
end
And using the loop I want a change of index "i"
Asa result Output have to be something like that: C={'portfolio 1','portfolio 2','portfolio 3','portfolio 4',......'portfolio 10'};
Hope to hear from you soon. Thanks in advance!
  1 件のコメント
Yusef Ghazwan
Yusef Ghazwan 2020 年 6 月 16 日
Show the output!

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Geoff Hayes
Geoff Hayes 2014 年 5 月 30 日
You can use the sprintf command to do what you require. Just modify your body of the for loop from what you have to
C{i} = sprintf('portfolio %d',i);
Note that since your code has defined C to be a cell array, the curly braces {} are used to access elements within it.
  1 件のコメント
Dmytro
Dmytro 2014 年 5 月 30 日
It is alive!!!! Thank you a lot!!!

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