Logical indexing and sums

2 ビュー (過去 30 日間)
Fabs
Fabs 2014 年 5 月 28 日
コメント済み: Fabs 2014 年 5 月 28 日
Hi,
first of: I know I can do what I want in a loop. However, I'm performing something similar to my problem thousands of times on much bigger matrices, so if there is a solution with logical indexing and without any loop, that would be preferred.
OK, let's assume I have a matrix
a=[23 45; 65 13];
and I want the values of a to written to new positions defined in
b=[2 4;1 2]; % matrix with new positions for values in a
Obviously b is referencing one position (2) twice and
c=nan(size(a));
c(b) = a % matrix with values from a at positions from b
results in
c = [65 13; NaN 45]; % location two is written twice and only the second value shows up
Is there a way to get matrix c to be
c = [65 36; NaN 45]; % location 2 is sum of 13+23
?
Thanks y'all, I appreciate your help, F

採用された回答

Kelly Kearney
Kelly Kearney 2014 年 5 月 28 日
Meet accumarray, my favorite powerful-and-useful-but-terribly-named function (and lately, seemingly the answer to every question I respond to):
c = reshape(accumarray(b(:), a(:), [numel(a) 1], @sum, NaN), size(a))
  1 件のコメント
Fabs
Fabs 2014 年 5 月 28 日
That's what I call a quick response! Thank you very much!

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeCreating and Concatenating Matrices についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by