Help me about the error with symsum function to calculate the sum of series ?
1 回表示 (過去 30 日間)
古いコメントを表示

I use symsum to calculate the sum of a series, with 1) and 2), it's ok. but with 3), the symsum does not have the result. Why ? help me about this error. Thanks very much.
0 件のコメント
回答 (1 件)
George Papazafeiropoulos
2014 年 5 月 28 日
Maybe because there is not any analytical formula which gives this sum. Can this function be integrated in an analytic way? I suppose no.
You can take the numerical result of the sum in this way:
k=1:10000;
sum1=sum(((k+1).^(1/2) - (k-1).^(1/2))./k.^2);
k=1:100000;
sum2=sum(((k+1).^(1/2) - (k-1).^(1/2))./k.^2);
and compare sum1 and sum2. The result is 1.763306701885209.
0 件のコメント
参考
製品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!