Time domain Vector problem

2 ビュー (過去 30 日間)
D
D 2014 年 5 月 23 日
コメント済み: Roger Wohlwend 2014 年 5 月 23 日
hi ,
i wish to preform the follwing :
m(t)=a(0)*p(t)+a(1)*p(t-T)+a(2)*p(t-2T)+...
where :
a(n)=[1 -1 1 -1 ] %randomize -1 or 1
p(t)=[1.2 ....] %Raised cosine filter with 1X8001
T=1e-3;
how can I time shift p(t) ?
  2 件のコメント
Azzi Abdelmalek
Azzi Abdelmalek 2014 年 5 月 23 日
What is the values of t? What are the values of p for t<0?
Roger Wohlwend
Roger Wohlwend 2014 年 5 月 23 日
I see several problems. (1) You cannot define a vector a(n) = [1 -1 1 -1]. Wrong sytax. Instead write a = [1 -1 1 -1]. (2) The same is true for vector p. Write p = [...] and not p(t) = [...]. (3) If you want a certain element of a vector, your index must be an non-negative integer. If you want the first element of vector a, you have to write a(1) and NOT a(0) as you did in the first line of code. (4) p(t-2T) is wrong syntax. Correct is: p(t-2*T)
Concering your question: What do you mean with time shifting p? You already do it in your first equation.

サインインしてコメントする。

回答 (0 件)

カテゴリ

Help Center および File ExchangeMathematics についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by