Matlab extract coefficient from z transform function

5 ビュー (過去 30 日間)
David
David 2014 年 5 月 10 日
コメント済み: Star Strider 2014 年 5 月 10 日
Hi I have a z transform function 3/z + 5/z^2 + 6/z^3 + 1
How would I extract the coefficients from this equation? I have tried using coeffs and it says it is not a polynomial.
I would like the answer to come out as [3 5 6 1]
The symbolic z variable is declared as syms z

採用された回答

Star Strider
Star Strider 2014 年 5 月 10 日
編集済み: Star Strider 2014 年 5 月 10 日
Use the sym2poly function, although here it’s necesary to do an intermediate step:
syms z
fz = 3/z + 5/z^2 + 6/z^3 + 1
[fzn, fzd] = numden(fz)
fzc = sym2poly(fzn)
fzc = circshift(fzc, [0 -1])
produces:
fzc =
3 5 6 1
  2 件のコメント
David
David 2014 年 5 月 10 日
Thank you so much for your input. It was exactly what I was looking for.
Star Strider
Star Strider 2014 年 5 月 10 日
My pleasure!
The sym3poly function would work with a ‘normal’ polynomial, but the symbolic terms in the denominator require numden and then circshift.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeCalculus についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by