second derivative of an image

4 ビュー (過去 30 日間)
jan
jan 2014 年 5 月 9 日
コメント済み: Image Analyst 2014 年 5 月 11 日
Hi every body
The contour of an object in one image is known as the points with second derivative equal to zero. How can i get this characteristic knowing that I have only the image (the pixels intensity)??
Please can any one help me, thanks a lot

回答 (1 件)

Nitin
Nitin 2014 年 5 月 10 日
There is a nice explanation on image derivative here . Please check it out, slide 23 onwards.
  4 件のコメント
jan
jan 2014 年 5 月 11 日
編集済み: jan 2014 年 5 月 11 日
Hi Nitin In fact, to obtain this characteristic we can apply the laplacien filter and this is what i tested before asking my question and this is the code that i used:
I=imread('image.png');
w=fspecial('laplacian',0);
g=imfilter(I,w,'replicate');
figure(1),imshow(g,[]);
but in g, the contour points aren't only the points with derivative equal to zeros there are other points inside and outside the object with derivative equal to zeros. So what i really need what i have tested is it true? and any explication or other suggested ideas because i need to characterise, in a formal manner the contour points to do a clustering thanks
Image Analyst
Image Analyst 2014 年 5 月 11 日
Why don't you post your image to help with your explanation about what you want to measure in the image?

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeGet Started with Image Processing Toolbox についてさらに検索

タグ

タグが未入力です。

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by