LSB in audio stegnography
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Muhammad fayyaz
2014 年 4 月 28 日
コメント済み: Walter Roberson
2016 年 3 月 31 日
% Embed message length in the first 16 samples
% (I don't understand how. Can any one explain?)
str = dec2bin(length(message),16);
if length(message) < length(y)
for a = 1 : length(str)
y(a, nbits-1) = str(a);
end
else
disp('error')
end
I don't understand how they are embedding here. Please help me.
1 件のコメント
採用された回答
Walter Roberson
2014 年 4 月 28 日
They are converting the message length to 16 text-coded binary locations, and are taking the resulting 16 bits and using them to replace the least significant bits of 16 successive text-coded binary representations.
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その他の回答 (2 件)
Muhammad fayyaz
2014 年 4 月 29 日
2 件のコメント
Walter Roberson
2014 年 4 月 29 日
Assume that the original signal has been converted into binary by using dec2bin(). dec2bin() returns an array of characters, each one being the character '0' or the character '1'. Then y(a,nbits-1) is a straight forward replacement of one element of the array with one element of the character vector "str".
Somewhere after this section of code, you will find a call to bin2dec(y) . That operation will take the character array y and convert the representation back into decimal numbers.
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