Doubts with parfor loop

2 ビュー (過去 30 日間)
Javier
Javier 2011 年 7 月 29 日
Hi, I'm a litte bit confused with error given in this parfor loop:
parfor n=1:fbaseDatosAct
veDelanteMiaTemp=zeros(1,3);
baseDatosRow = baseDatosAct(n,:);
veDelanteMiaTemp=vehDelanteMia(baseDatosAct,n,t);
[baseDatosRow(1),estaParado]=reduceVelocidad(t,baseDatosRow,vmin,veDelanteMiaTemp,pasoTemp);
baseDatosAct(n,:) =baseDatosRow;<-HERE TROUBLE WITH PARFOR!!
end
Why in the last sentence do I get a error saying that I cannot use parfoor loop due to the baseDatosAct use?? I've got another code whit a similiar use and I don't get this warning.
Another doubt, I can use pafor loop with logical indexing a matrix like this:
for n=1:1:fbDActual
indice=find(bDAnterior(:,columnaID)==bDActual(n,columnaID));
do something...
end
end
Where bDAnterior and bDActual both are matrixes of nx8.
Thanks Javier

回答 (1 件)

Edric Ellis
Edric Ellis 2011 年 8 月 1 日
The problem is that you're using the whole value of 'baseDatosAct' in the line:
veDelanteMiaTemp=vehDelanteMia(baseDatosAct,n,t);
Is that what you intended? If so, the loop is not order-independent because you're updating 'baseDatosAct' and using the values next time around the loop.
  1 件のコメント
Javier
Javier 2011 年 8 月 1 日
Yes it was. I have to use the whole value of 'baseDatosAct' in the function,however, I found out a solution doing this:
bdAct=zeros(fbaseDatosAct,cbaseDatosAct);
bdAct=baseDatosAct;
parfor n=1:fbaseDatosAct
veDelanteMiaTemp=zeros(1,3);
baseDatosRow = bdAct(n,:);
[veDelanteMiaTemp(1),veDelanteMiaTemp(2),veDelanteMiaTemp(3)]=vehDelanteMia(baseDatosAct,n,t);
[baseDatosRow(1),estaParado]=reduceVelocidad(t,baseDatosRow,vmin,veDelanteMiaTemp,pasoTemp);
bdAct(n,:) =baseDatosRow;
end
baseDatosAct=bdAct

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeLoops and Conditional Statements についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by