how to express a formula for modelFun fo nlinfit

2 ビュー (過去 30 日間)
Donatas
Donatas 2014 年 4 月 3 日
編集済み: Star Strider 2014 年 4 月 3 日
Hello, guys,
I have the formula (convolution):
where
and C is a matrix 1x40 and t is also a matrix of 1x40.
I want to use the first formula for non-linear least square fit (nlinfit), but I don't know how to write modelFun to express this formula, where MTT is a parameter, which I need to estimate.
Thanks for a reply!
Donatas

採用された回答

Star Strider
Star Strider 2014 年 4 月 3 日
編集済み: Star Strider 2014 年 4 月 3 日
I made several guesses as to what you are doing, but this seems to work:
% Create data:
t = linspace(0, 1, 40);
C = t;
% y = conv(t,exp(-t),'same');
y = conv(exp(-t/7),t);
% Objective function for curve fit
% w = @(P,t) conv(C, exp(-t/P),'same');
w = @(P,t) conv(C, exp(-t/P));
xv = 0:length(y)-1;
B = nlinfit(t, y, w, 1)
yp = w(B,t);
figure(1)
plot(xv, y, 'xb')
hold on
plot(xv, w(B,t), '-r')
hold off
grid
Note that there are 'full', 'same' and 'valid' options with the conv function. Use the one that most closely suits your needs.

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeStatistics and Machine Learning Toolbox についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by