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What determines the shape of a logically indexed array?

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Ondrej Budac
Ondrej Budac 2014 年 4 月 3 日
回答済み: Ondrej Budac 2014 年 4 月 7 日
Matlab help explains: " Logical Indexing : ... The output is always in the form of a column vector."
In practice, typing
a = ones(3,3);
b = a([true, true]);
gives a row vector b. Can someone tell me why does it behave this way? And is there any other instance (apart from indexing by one row logical vector) that gives a non-column result? Thanks, O.

採用された回答

Ondrej Budac
Ondrej Budac 2014 年 4 月 7 日
Just to complete the story, the answer seems to be:
If B is a logical array and A is any array, then A(B) is equivalent (but faster) way to produce the same result as A(find(B)), including the shape of the output.

その他の回答 (1 件)

Azzi Abdelmalek
Azzi Abdelmalek 2014 年 4 月 3 日
Maybe you need
a = ones(3,3);
b = a([true, true],:)
  7 件のコメント
Azzi Abdelmalek
Azzi Abdelmalek 2014 年 4 月 3 日
Just one question, what are you expecting with a(logical([1 0;1 1])) ? The result contains 3 elements
Ondrej Budac
Ondrej Budac 2014 年 4 月 3 日
If I now understand logical indexing correctly, I expect a(logical([1 0;1 1])) to give a column vector with values 1, 4, 2, assuming your definition of a.

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