sort vector elements under given restrictions

Hi guys,

i have the vector v=[1 2 3 4 5]

wanna resort it so that v(3) and v(5) comes first:

v=[3 5 others] % 'others' has any order

How can i do that? The problem here is exactly this: how to write 1:5 but missing 3 and 5 .

Any idea? thx...

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PS: this question is related to

http://www.mathworks.de/matlabcentral/answers/122208-permute-matrix-dimensions-getting-trickier

The point relating to this cited question is that i can find all combinations (just for-loop), but i cannot arrange the rest of the dimensions. Thus this present question.

Thx...

Answer 1

[zepp]

You can create a logical array (same length as v) with 1's for the positions you want (say, 3 and 5) and 0's for the rest and use that to refer to the indices.

v = [1 2 3 4 5]
ind = [0 0 1 0 1]
v = [v(ind==1) v(~ind==1)]

Answer 2

[oxy]

Great! Thx!

Just another question: This is the way I've been doing it on octave. I wander why it doesnt work in matlab!!! :-/

    vector2sort= 1:6
    n=length(vector2sort)
    a=2; b=4 % i.e. I wanna the 2nd and 4th elements of vector2sort first
    [a b (1:n)( (1:n)!=a & (1:n)!=b )] % this is how we sort it

Why it does not work in matlab?!! Is there a way to do it more simila?

thx 4 your wisdom!

[zepp]

The concept is fine, but you can't reference array elements like that in Matlab.

Try this out:

v = 1:6;
a = 2; b = 4;
sortedv = [a b v(v~=a & v~=b)];