Create two vectors X and Y of values from (-pi) to pi with a spacing of pi/10. Define the vector Z as: Z = (sin(sqrt(x^2+y^2)))/(sqrt(x^2+y^2))
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Im trying to plot function. I have wrote x=[-pi:pi/10:pi] and y=[-pi:pi/10:pi]. Also Z = (sin(sqrt(x.^2+y.^2)))/(sqrt(x.^2+y.^2)). When I try to plot the function z somehow gets to be only one number such as -0.0227 and I get error 'Vectors must be the same lengths'. Please help me to get this problem right
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Roger Stafford
2014 年 3 月 18 日
You need to put a "dot" in your division operator:
Z = (sin(sqrt(x.^2+y.^2)))./(sqrt(x.^2+y.^2))
What you had there without the dot was matrix division which in this case produces a single scalar.
I am curious though as to what you are trying to do. Both the x and y vectors are identical. It looks as though you were attempting to accomplish something other than what you produced in the code. If so, please tell what that is.
その他の回答 (2 件)
Marta Salas
2014 年 3 月 18 日
編集済み: Marta Salas
2014 年 3 月 18 日
[x,y] = meshgrid(-pi:pi/10:pi)
z = (sin(sqrt(x.^2+y.^2)))./(sqrt(x.^2+y.^2))
mesh(x,y,z)
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