how to judge the intersection point of normal equations with matlab?
8 ビュー (過去 30 日間)
古いコメントを表示
I want to judge the intersection point of normal equation,and get the intersection point coordinate. For example, there are five normal equations of five surfaces. Assume the intersection point coordinate is (x0,y0,z0).
eq1: 2*(x-x0)+3*(y-y0)-(z-z0)+5=0
eq2: 6*(x-x0)+4*(y-y0)-(z-z0)+7=0
eq3: 1*(x-x0)+2*(y-y0)-(z-z0)+3=0
eq4: 4*(x-x0)+3*(y-y0)-(z-z0)+8=0
eq5: 3*(x-x0)+2*(y-y0)-(z-z0)+2=0
Thanks very much in advance
1 件のコメント
Roger Stafford
2014 年 3 月 12 日
編集済み: Roger Stafford
2014 年 3 月 12 日
You have me confused, Rui. If we set x, y, and z to x0, y0, and z0, none of the equations is satisfied. In what sense then is (x0,y0,z0) an "intersection point"?
Besides this objection, what you have here is an overdetermined set of equations. There are five equations and only three unknowns to adjust. In general there will be no solutions for them. In other words, what makes you assume that the five different planar surfaces will all intersect in a common point? (In fact they do not intersect!)
回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Assembly についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!