how to judge the intersection point of normal equations with matlab?

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rui
rui 2014 年 3 月 12 日
編集済み: Roger Stafford 2014 年 3 月 12 日
I want to judge the intersection point of normal equation,and get the intersection point coordinate. For example, there are five normal equations of five surfaces. Assume the intersection point coordinate is (x0,y0,z0).
eq1: 2*(x-x0)+3*(y-y0)-(z-z0)+5=0
eq2: 6*(x-x0)+4*(y-y0)-(z-z0)+7=0
eq3: 1*(x-x0)+2*(y-y0)-(z-z0)+3=0
eq4: 4*(x-x0)+3*(y-y0)-(z-z0)+8=0
eq5: 3*(x-x0)+2*(y-y0)-(z-z0)+2=0
Thanks very much in advance
  1 件のコメント
Roger Stafford
Roger Stafford 2014 年 3 月 12 日
編集済み: Roger Stafford 2014 年 3 月 12 日
You have me confused, Rui. If we set x, y, and z to x0, y0, and z0, none of the equations is satisfied. In what sense then is (x0,y0,z0) an "intersection point"?
Besides this objection, what you have here is an overdetermined set of equations. There are five equations and only three unknowns to adjust. In general there will be no solutions for them. In other words, what makes you assume that the five different planar surfaces will all intersect in a common point? (In fact they do not intersect!)

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