INTERSECTION BETWEEN 2 IMAGES

Hi everyone (sorry for bad english).

I need code to find the intersection between two images. I have image A and image Am (is the modified version of image A) and I have to find points in common or the area (teacher suggest I use the intersection). Then repeat the process for 100 images in a folder.

Answer 1

[Image Analyst]

You can subtract them and look for 0's. For grayscale images:

matchingPixels = (double(image1) - double(image2)) == 0;
imshow(matchingPixels);

To find area of matching pixels, you can use sum(), bwarea() or regionprops():

area1 = sum(matchingPixels);
area2 = bwarea(matchingPixels);
% To use regionprops to find areas of all matching regions.
labeledImage = bwlabel(binaryImage);
measurements = regionprops(labeledImage, 'Area');
area3 = sum([measurements.Area]);

For color images, you have to check each color channel for matches.

For binary images use the dice() function, introduced in R2017b:

Description

similarity = dice(BW1,BW2) computes the Sørensen-Dice similarity coefficient between binary images BW1 and BW2.

To process a sequence of files, see the FAQ:

https://matlab.fandom.com/wiki/FAQ#How_can_I_process_a_sequence_of_files.3F

[Diah Junaidi]

what should I do for sir? i have 2 binary images that I wanna compare.

labeledImage = bwlabel(binaryImage);

[Image Analyst]

In what way do you want to compare these binary images? Maybe:

Description

example

similarity = dice(BW1,BW2) computes the Sørensen-Dice similarity coefficient between binary images BW1 and BW2.

Answer 2

[Azzi Abdelmalek]

[M,ii,jj]=intersect(A,Am)

Answer 3

[Mohsin Khalid]

1) Convert them in to gray scale images 2) Then convert them in to binary images

Below is a command for intersection of two images

 intersectedImage=bitand(binaryImage1,binaryImage2);

For 100 images take the intersectedImage and bitand it with binaryImage3 and so on..

[Walter Roberson]

If you take that approach, the output will only be set at places where both images had intensity greater than or equal to 128 (out of 255), which is not what the user is asking. The user is asking for points that are in common, which includes places where both are both the same low intensity.