plotting tan(x) - basic student's question
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I am new to matlab and have been trying to plot basic things.
I have sucessfully managed to plot sin(x) by doing the following:
x = -2*pi:pi/100:2*pi; y = sin(x); plot(x,y)
However, when I replace the sin(x) by tan(x), the plot does not come out right. I can't figure out why this is. On the other hand I have managed to plot tan(x) using ezplot...
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Mischa Kim
2014 年 2 月 27 日
編集済み: Mischa Kim
2014 年 2 月 27 日
Will, tan(x) has singularities (function goes to infinity) at pi/2 +/- n*pi. So when you plot over the range from -2*pi to +2*pi the data points just before and right after such a singularity will also be connected (by the default line), unless you tell MATLAB to ploint data points only (markers, essentially). For example,
plot(x,y,'*')
Plus, you would also want to put a limit on your y-axis, something like
ylim([-10 10])
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その他の回答 (3 件)
Wayne King
2014 年 2 月 27 日
編集済み: Wayne King
2014 年 2 月 27 日
tan(x) is periodic with period pi and "blows up" at odd multiples of pi/2 so why not just plot one period?
dx = 0.01;
x = -pi/2+dx:pi/100:pi/2-dx;
y = tan(x);
plot(x,y)
by increasing dx, you'll get a better visual because the value near +/- pi/2 grows in magnitude so quickly, the plot becomes dominated by the large negative and positive values,
dx = 0.1;
x = -pi/2+dx:pi/100:pi/2-dx;
y = tan(x);
plot(x,y)
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