create a matrix based on a row distribution

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pavlos
pavlos 2014 年 2 月 9 日
回答済み: Roger Stafford 2014 年 2 月 9 日
Hello,
Please help me with the following.
Consider a 100x10 matrix A and a 15x10 matrix B.
We also have a distribution i=1,2,...,15 of the rows of A.
For example,
A=[row1;row2;...;row100];
The distribution of the 15 values is random:
distr=[6;14;...;2];
The distr vector is 100x1.
How can we replace the corresponding rows of B to A, based on the distribution?
The new matrix A, called A_new, is also 100x10 and should like this:
A_new=[B(6,:);B(14,:);...;B(2,:)];
The A_new rows are the corresponding rows of B based on the distribution.
Thank you very much.
Best,
Pavlos

採用された回答

Roger Stafford
Roger Stafford 2014 年 2 月 9 日
A_new = B(distr,:);

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