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Implementation of Snake Algorithmm for finding contours of Hand

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Explorer
Explorer 2014 年 2 月 6 日
I am following a research paper in which contour of hand is determined as shown in Figure 4.
In this paper, snakes were used to perform segmentation. A snake can be defined as an energy-minimizing spline guided by external restraining forces and influenced by image forces, which tends to localize it in features such as lines and edges. It is therefore an active contour that evolves dynamically relevant to the contours of the image. The snake is represented as a parametric curve by r(s) = (x(s),y(s)), with s(0, 1). Its functional energy can be expressed as:
Where Eint represents the internal energy of the snake, Eimg image forces and Eres external restraining forces.
Can you help in coding for this?
This is the image whose contours I need to find.
  4 件のコメント
Walter Roberson
Walter Roberson 2014 年 2 月 7 日
Asking how to proceed is an algorithms or theory question, not a MATLAB question.
Amelia Kartika
Amelia Kartika 2018 年 2 月 24 日
How this coding for procced

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採用された回答

Image Analyst
Image Analyst 2014 年 2 月 6 日
See my activecontour demo, attached. It will find the hand.
  16 件のコメント
Amy Phan
Amy Phan 2017 年 4 月 2 日
I tried this code but I'm not receiving any outline for my image. This is the outcome:
The image I'm using is an MRI image and I'm trying to use the snake method to outline the heart but I'm having issues with the thresholding. Any suggestions?
Nhat Nguyen Thanh Minh
Nhat Nguyen Thanh Minh 2020 年 10 月 29 日
try other threshold values

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その他の回答 (2 件)

snehal jaipurkar
snehal jaipurkar 2017 年 11 月 22 日
Sir how to save the segmented image after applying snake model in Matlab?????

snehal jaipurkar
snehal jaipurkar 2017 年 11 月 22 日
And also I want to create a mask of the segmented image by putting the segmented part with intensity 1 and the rest of the part as zero. So how can I do that... Please please tell as soon as possible. Thanks alot in advance.
  1 件のコメント
Image Analyst
Image Analyst 2017 年 11 月 22 日
My code does that. It's the "bw" in this line of code:
bw = activecontour(grayImage, mask, 400, 'edge');

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