How to code this? Resampling of vector
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Hi all,
Currently I am trying to resample a signal by changing its signal frequency; The signal is given by time vector t and signal vector s. Example:
t=[ 1 2 3 4 5 6 7 8 9 10 11 12]
s=[3 3.5 3 5.5 2 2.5 3 5 7 2.5 3.5 4 ]
I want to create a vector s_new in which the sum of the values of s on the interval <0,4] is one element, the sum of interval <4,8] is an element etc, creating:
s_new= [15 12.5 17]
I have been toying around with histc but didnt succeed. Any ideas on coding this?
Thanks in advance! Lucas
1 件のコメント
Azzi Abdelmalek
2014 年 2 月 5 日
Lucas commented
Thanks guys, but I actually want to use any resampling frequency, so the reshape command doesnt necessarily work (works only if old and new sampling times are integer multiples of each other). Thanks anyway!
採用された回答
Mischa Kim
2014 年 2 月 5 日
編集済み: Mischa Kim
2014 年 2 月 5 日
For these straightforward time values, this will do
sum(reshape(s,4,3))
If t gets more complex you should be able to find a similar solution, though.
0 件のコメント
その他の回答 (2 件)
David Sanchez
2014 年 2 月 5 日
s_new(1) = sum(s(find(s<4)))
s_new(2) = sum(s(find( (s<8)&(s>=4) )))
s_new(3) =sum(s(find( (s<12)&(s>=8) )))
...
0 件のコメント
Azzi Abdelmalek
2014 年 2 月 5 日
編集済み: Azzi Abdelmalek
2014 年 2 月 5 日
t=[ 1 2.5 2.8 3 3.1 4 5 6 7 8 9 10 11 12];
s=[3 3.5 3.5 4 3 5.5 2 2.5 3 5 7 2.5 3.5 4 ]
ii=hist(t,[2 6 10]) % 2 is the middle of the interval [0,4];
ii2=cumsum(ii);
ii1=[1 ii2(1:end-1)+1];
out=arrayfun(@(ii,jj) sum(s(ii:jj)),ii1,ii2)
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