If I have
A1 =
1.0e-013 *
Columns 1 through 8
0.1481 0.1574 0.1465 0.1481 0.1574 0.1465 0.1481 0.1574
Column 9
0.1465
And
A2 =
1.0e-013 *
Columns 1 through 8
0.1250 0.1523 0.1465 0.1250 0.1523 0.1465 0.1250 0.1523
Column 9
0.1465
How can I plot either variables, on the same bar plot?
bar([A1 A2])
legend('A1,'A2')
If MATLAB said:
Warning: Ignoring extra legend entries.
> In legend at 278
What's the mistake?

 採用された回答

Azzi Abdelmalek
Azzi Abdelmalek 2014 年 1 月 31 日
編集済み: Azzi Abdelmalek 2014 年 1 月 31 日

0 投票

A1 =1.0e-013 *[ 0.1481 0.1574 0.1465 0.1481 0.1574 0.1465 0.1481 0.1574]
A2= 1.0e-013 *[0.1250 0.1523 0.1465 0.1250 0.1523 0.1465 0.1250 0.1523]
bar([A1' A2'])
legend('A1','A2')

6 件のコメント

Francesco
Francesco 2014 年 1 月 31 日
If there are so many elements in A1 and A2 and, a priori, I don't Know how many elements, how can I do it?
Azzi Abdelmalek
Azzi Abdelmalek 2014 年 1 月 31 日
What do you mean by so many element? give an example
Francesco
Francesco 2014 年 1 月 31 日
The A1 and A2 variables are define before in the code. In this case A1 is 1x9 double and also A2. But it may be 1xn double for A1 and A2. If A1=A2=1xn, I can't do as you said because I have not entire into the code.
Azzi Abdelmalek
Azzi Abdelmalek 2014 年 1 月 31 日
(I have not entire into the code): This sentence is not clear for me
Francesco
Francesco 2014 年 1 月 31 日
But If I have A1 and A2 variables, for example, A1=A2=1*n how I can do the bar plot?
Azzi Abdelmalek
Azzi Abdelmalek 2014 年 1 月 31 日
The same as the above answer
bar([A1' A2'])
legend('A1','A2')

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