change values in a matrix
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I have a big matrix and I want to correct it The first column I want to remove those -1 and -2 from my data
for example my data is as follows
0,206470489501953 -1,86300277709961 -2,64120101928711
0,270366668701172 -1,92737579345703 -2,63929367065430
0,382900238037109 -1,87778472900391 -2,54106521606445
0,349044799804687 -1,72615051269531 -2,34174728393555
0,287532806396484 -1,63698196411133 -2,47240066528320
I want to have it as follows
0,206470489501953 0,86300277709961 0,64120101928711
0,270366668701172 0,92737579345703 0,63929367065430
0,382900238037109 0,87778472900391 0,54106521606445
0,349044799804687 0,72615051269531 0,34174728393555
0,287532806396484 0,63698196411133 0,47240066528320
nothing changed , I just removed the minus 1 and minus 2 from my data
Unfortunately, I cannot use abs function since I have also big numbers in my data that i cannot touch like follows;
46,5722084045410 110,708236694336 3,10182571411133
44,4703102111816 108,825206756592 4,81796264648438
42,4933433532715 106,929779052734 6,19792938232422
40,4911041259766 104,907035827637 6,72531127929688
I only need to remove those -1, -2, -3 from my data but not changing the positive values with higher than 1 like above
4 件のコメント
採用された回答
Jos (10584)
2014 年 1 月 30 日
編集済み: Jos (10584)
2014 年 1 月 30 日
Another problem needs another solution:
a = [0.1234 -1.9876 -2.0001 22.9999]
b = a % work on a copy
q = fix(b)<0
b(q) = abs(rem(b(q),1))
0 件のコメント
その他の回答 (3 件)
Mischa Kim
2014 年 1 月 30 日
編集済み: Mischa Kim
2014 年 1 月 30 日
A = [0.1 -2.3]
A =
0.100000000000000 -2.300000000000000
abs(rem(A,1))
ans =
0.100000000000000 0.300000000000000
2 件のコメント
Azzi Abdelmalek
2014 年 1 月 30 日
編集済み: Azzi Abdelmalek
2014 年 1 月 30 日
idx=A<=-1
A(idx)=A(idx)-fix(A(idx))
Jos (10584)
2014 年 1 月 30 日
For numerical arrays use REM and ABS. An example:
a = [0.1234 -1.9876 -2.0001]
b = abs(rem(a,1))
% [0.1234 0.9876 0.0001] as required
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