heres my code.... getting an error ? Error using ==> horzcat CAT arguments dimensions are not consistent. Error in ==> practice at 3 result=[x(:),y(:),h(:)]; please help????????

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Prasad
Prasad 2014 年 1 月 28 日
コメント済み: Image Analyst 2014 年 1 月 28 日
h=double(imread('evening.jpg'));
[x,y]=meshgrid(1:size(h,1), 1:size(h,2));
result=[x(:),y(:),h(:)];

回答 (2 件)

Anuj
Anuj 2014 年 1 月 28 日
The number of rows in x,y,h are not same, so they cannot be concatenated. check your matrix dimensions.
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Prasad
Prasad 2014 年 1 月 28 日
sorry.. but im completely new to matlab. can u pls help me out finding the co ordinates of an image. my ultimate aim is to perform skewing!!!

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Image Analyst
Image Analyst 2014 年 1 月 28 日
編集済み: Image Analyst 2014 年 1 月 28 日
Why? You don't need to do that (call meshgrid). You don't need to get the row, column coordinate of every single pixel in your image. Why not just call imtransform() to do skewing? By the way, you didn't even call it correctly. You mixed up x and y with rows and columns. x is columns, not rows and not gotten from size(h, 1).
  2 件のコメント
Prasad
Prasad 2014 年 1 月 28 日
編集済み: Prasad 2014 年 1 月 28 日
ohh.. thanx. i would be very grateful if u could provide me with a sample code werin imtransform() has been utilized to perform skewing... thank you in advance!!!
Image Analyst
Image Analyst 2014 年 1 月 28 日
Did you look at it yet? Don't you want what they call shear in their first example in the help?
I = imread('cameraman.tif');
tform = maketform('affine',[1 0 0; .5 1 0; 0 0 1]);
J = imtransform(I,tform);
imshow(I), figure, imshow(J)

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