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Replace matrix with the other random matrix.

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Andi Tarigan
Andi Tarigan 2014 年 1 月 27 日
編集済み: Walter Roberson 2016 年 4 月 16 日
Hello,
Here I have matrix vector 0 and 1 with size (1024, 1), and I have the other matrix from random matrix with value between 0 and 1, with a seed (rng function), so the output of this matrix not change, and length this matrix dependent how much vector 0 and 1 in the first matrix. And I want to replace the first matrix (1024, 1) with the second matrix, but must equal with the vector, 0 or 1. And the output matrix which changed have the value random (between 0 until 1) with size (1024, 1). How can I make it? Thank you.
  2 件のコメント
Amit
Amit 2014 年 1 月 27 日
The question is a bit confusing. Can you rephrase it with an example (probably take the matrix as size (5,1))
Andi Tarigan
Andi Tarigan 2014 年 1 月 27 日
編集済み: Walter Roberson 2016 年 4 月 16 日
arnold_new = reshape(arnold, 1024, 1); % Make the matrix to 1 column
find_0 = find(arnold_new == 0); % Total bit 0
find_1 = find(arnold_new == 1); % Total bit 1
size_0 = size(find_0);
size_1 = size(find_1);
% =========================================================================
% Program to generate pseudorandom bit 0
% =========================================================================
rng(0) % Seed for bit 0
null = rand(size_0); % Total random value bit 0
null_new = reshape(nol, length(null_new), 1); % Make matrix to 1 column
% =========================================================================
% Program to generate pseudorandom bit 0
% =========================================================================
rng(1)% Seed for bit 1
one = rand(size_1); % Total random value bit 0
one_new = reshape(one, length(one_new), 1); % Make matrix to 1 column
And how i can changed the arnold_new matrix with the pseudorandom sequence in null_new and one_new? So that output is random, not bit 0 or 1 as arnold_new.

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採用された回答

Amit
Amit 2014 年 1 月 27 日
編集済み: Amit 2014 年 1 月 27 日
How about simply:
rng(0);
arnold_new_null = rand(size(arnold_new));
rng(1);
arnold_new_ones = rand(size(arnold_new));
arnold_new(arnold_new == 1) = arnold_new_ones(arnold_new == 1);
arnold_new(arnold_new == 0) = arnold_new_nulls(arnold_new == 0);
  7 件のコメント
Amit
Amit 2014 年 1 月 27 日
rng(0);
arnold_new_null = rand(1024,1);
rng(1);
arnold_new_one = rand(1024,1);
Andi Tarigan
Andi Tarigan 2014 年 1 月 27 日
Okay. Thankyou sir!

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その他の回答 (1 件)

Azzi Abdelmalek
Azzi Abdelmalek 2014 年 1 月 27 日
Maybe you want this:
a=randi([0 1],1,10);
s=rng;
b=rand(1,10);
out=a.*b
  3 件のコメント
Azzi Abdelmalek
Azzi Abdelmalek 2014 年 1 月 27 日
a=randi([0 1],1,10);
s1=rng;
b1=rand(1,10);
s2=rng;
b2=rand(1,10);
out=zeros(size(a))
out(a==1)=b1(a==1)
out(a==0)=b2(a==0)
Andi Tarigan
Andi Tarigan 2014 年 1 月 27 日
It works! Thankyou sir!

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