Error using horzcat in a for loop
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Hi everyone, I am testing a for loop and it is showing me some error in the horzcat, I do not know why it does. Can anyone explain me why it happens, and help me to fix my code. Thank you
p=1;
[row,col] = size(A);
for i = 1:row
for j=1:col
if(A(i,j)>0)
z(p,:)=[j,i];
p=p+1;
end
end
end
B=[(1:p-1)',z]
This is the error:
Error in ==> testloop at 11
B=[(1:p-1)',z]
??? Error using ==> horzcat
CAT arguments dimensions are not consistent.
Error in ==> testloop at 11
B=[(1:p-1)',z];
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採用された回答
kjetil87
2014 年 1 月 21 日
編集済み: kjetil87
2014 年 1 月 21 日
horzcat concatinates arrays in horizontal direction i.e x = [a , b] is horzcat. when you call B=[(1:p-1)' ,z] your are calling horzcat (there is also a version called vertcat).
The problem is that (1:p-1)' and z does not have the same amount of rows. Which is strange, because your code looks correct. perhaps z allready existed before you ran the code? try adding
clear z;
before your loop.
or
B=[(1:p-1)' , z(1:p-1,:)];
その他の回答 (1 件)
Amit
2014 年 1 月 21 日
I think I figured it out.
This error must be occurring not everytime. The thing that if you run this few time, the size of z can change. But as you did not cleared the z from previous run, in new case (where size of z should be lower), the new value only replace in the previous locations and does not update the size of z. Try the code below. this will work.
p=1;
[row,col] = size(A);
clear z; % This is needed
for i = 1:row
for j=1:col
if(A(i,j)>0)
z(p,:)=[j,i];
p=p+1;
end
end
end
B=[(1:p-1)',z]
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