How can I built a new matrix in a new method?

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Ayob
Ayob 2014 年 1 月 18 日
コメント済み: Paul 2014 年 1 月 18 日
I have a matrix like Assem{1} which is equal to:
Assem{1}=[0 6 2 0 0 7 0 0 0 12 3 0 1]
My another matrix is:
C=[W1 W2 W3 W4 W5 W6 W7 W8 W9 W10 W11 W12 W13], (W1 to W13 are defined values)
I want to use " D(Assem{i})=C " to define a new matrix D which is assembeled by members of matrix C with the help of matrix Assem{1}.
But, As you see some members of Assem{1} have zero values and doesn't lead to any position in D. So, I want to clear members with zero values of matrix Assem{1} and it's equivalent members in matrix C in order to be able built my matrix with the method of " D(Assem{i})=C ".
So
Assem{1} shold change to Assem{1}=[6 2 7 12 3 1]
C should change to C=[W2 W3 W6 W10 W11 W13]
How can I do these two steps with Matlab matrix methods.
[Note: Assem{i} has different values, I mentioned Assem{1} for i=1 as an example]

採用された回答

Paul
Paul 2014 年 1 月 18 日
ind = find(Assem{1}==0);
Assem{1}(ind)=[];
C(ind)=[];
  2 件のコメント
Ayob
Ayob 2014 年 1 月 18 日
This is not right . My program should find zero members in Assem{1} and then clear for example second member and fourth member in Assem{1} which are zero and then clear second and fourth members in matrix C whether they are zero or not.
Paul
Paul 2014 年 1 月 18 日
That code does exactly what you describe. If not, tell me why it's wrong according to you.

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