Code bug with image algorithm
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Hello there,
Here's a part of the code that I'm using to approximate an image and I'm kind of not understanding the problem with the last line. I'm suspecting there's something wrong with the datatype of m. The value of m is (sqrt(M)-1)/2 where M is the number of coefficients.
sizeImage = size(riceImage,1);
A = zeros(sizeImage);
sel = (sizeImage/2-m:sizeImage/2+sizeImage)+1;
A(sel,sel) = B(sel,sel);
1 件のコメント
José-Luis
2014 年 1 月 16 日
It would be helpful if you posted the error you get.
回答 (1 件)
Image Analyst
2014 年 1 月 16 日
Try this:
sizeImage = size(riceImage, 1); % Number of rows only (not # columns)
A = zeros(sizeImage); % rows by rows square image.
halfWidth = int32(sizeImage/2); % Round to nearest integer.
% The remaining code will go out of bounds and is nonsense.
% At least I don't understand the intent of it.
sel = (halfWidth -m : halfWidth + sizeImage)+1; % Maybe try end instead of sizeImage
A(sel,sel) = B(sel,sel); % No idea what this is supposed to do.
1 件のコメント
Walter Roberson
2014 年 1 月 17 日
sizeImage/2+sizeImage is going to be greater than sizeImage so you are attempting to index outside the "A" that you defined.
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