convert strings back to variable names?
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I copied a piece of code below. xs, ys and zs contain strings that happen to be variable names, and I'm checking to see if these variables exist using the find.. = ismember() function. Each of those strings that are variable names are variables whos values are arrays and I'd like to concatenate whatever variables do exist.
For example: if x1a and xA exist, I want to join both of those arrays to make one array stored in grids2project.x.xgrdc(i) = [x1a;xA]. (This piece of code is in a for-loop, hence the (i)). The code below just gives me the strings when i set the value = xs(findxs).
xs = {'x1a','x2b','xA'};
findxs = ismember(xs,who);
ys = {'y1a','yB','y2c'};
findys = ismember(ys,who);
zs = {'zC','z1b','z2c'};
findzs = ismember(zs,who);
grids2project.x.(genvarname(['xgridc' num2str(i)],who)) = xs(findxs);
grids2project.y.(genvarname(['ygridc' num2str(i)],who)) = ys(findys);
grids2project.z.(genvarname(['zgridc' num2str(i)],who)) = zs(findzs);
Thanks!
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採用された回答
Fangjun Jiang
2011 年 7 月 9 日
In this case, you need to use eval() to get its value.
a=1; VarName={'a','b','c'}; eval(VarName{1})
Use ismember() and who() is a good way to check existing variables. I wonder if you know this function. exist('a','var');
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その他の回答 (1 件)
Paulo Silva
2011 年 7 月 9 日
Just a simple example on how to create 3 variables with predetermined values.
v={'x1a','x2b','xA'};
values={10,20,30};
for n=1:numel(v)
vn=values(n);
assignin('base',char(v(n)),vn{:})
end
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