Read files in zip file without unzipping

180 ビュー (過去 30 日間)
Etienne Coetzee
Etienne Coetzee 2011 年 7 月 5 日
コメント済み: Mark Gugliuzza 2023 年 3 月 21 日
Hi there
I have a zip file with about 100 binary files in. I have a routine to read the files into matlab variables. Is there a way that I can read the files directly without unpacking the zip file?
Thanks in advance.
Etienne
  1 件のコメント
Jan
Jan 2011 年 7 月 6 日
What do you want to do with a zipped variable? Do you want to unzip one of the files only?

サインインしてコメントする。

回答 (4 件)

Bob Hamans
Bob Hamans 2011 年 7 月 6 日
Hi Etienne. I don't know if I understand your question but you just want to list the zip file contents without unzipping? The following code does just that:
function filelist = listzipcontents(zipFilename)
% Create a Java file of the ZIP filename.
zipJavaFile = java.io.File(zipFilename);
% Create a Java ZipFile and validate it.
zipFile = org.apache.tools.zip.ZipFile(zipJavaFile);
% Extract the entries from the ZipFile.
entries = zipFile.getEntries;
% Initialize the file list.
filelist={};
% Loop through the entries and add to the file list.
while entries.hasMoreElements
filelist = cat(1,filelist,char(entries.nextElement));
end
end
  5 件のコメント
Lars Janssen
Lars Janssen 2021 年 3 月 1 日
For those using the code snippet above, please add:
zipFile.close
This will "unlock" the java file again. After having some trouble deleting the zip file I found this missing piece of code here:Extracting specific file from zip in matlab - Stack Overflow.
Mark Gugliuzza
Mark Gugliuzza 2023 年 3 月 21 日
Does anyone know if it is possible to perform this recursively? I have zips within zips that I need to read all the file names out of?

サインインしてコメントする。


Etienne Coetzee
Etienne Coetzee 2011 年 7 月 6 日
Ok, thanks Robert. I will log it as an enhancement.

Robert Cumming
Robert Cumming 2011 年 7 月 6 日
have you seen this thread - you could try what it suggests in your own copy of unzip.m - or send an enhancement request to Mathworks.
Its actually quite easy to update the m file(s):
1. Change the number of accepted input arguments to 3.
2. Handle the third input agument (say a cell array of requested files) or set to default (empty cell array)
3. Pass the 3rd argument into the private function extractArchive
4. In the private function do a strcmp on the entryName and your cell array of requested file(s) - if match found extract, if not skip to next (use continue in the while loop)

Brunno Machado de Campos
Brunno Machado de Campos 2018 年 1 月 11 日
Hi, If anyone is until interested, for zip, on Windows (where I tested):
a = fopen('ZIPFILENAME.zip','r');
c2 = fread(a,'uint8=>uint8');
zipname = char(c2(31:31+c2(27)-1));
zipname = strcat(zipname')
  2 件のコメント
Chris Piker
Chris Piker 2020 年 5 月 6 日
I like it. Thanks! I'll look into the zip binary format a bit more.
Collin Pecora
Collin Pecora 2020 年 6 月 24 日
Allows for extracting specific file from a zip archive.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeSoftware Development Tools についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by