Using nested loops to solve kronecker product

dear all, my question is how do solve kronecker's product of a 10x10 matrix or any matrix size using nested loops rather than the conventional Kron function.

for eg,

aa=round(rand(10,10)*10-5)
bb=round(rand(10,10)*20-10)

what do i write in the script to solve the multiplication of aa*bb using kroneckers rule.

thanks!

Answer 1

[sixwwwwww]

you can do it as follows(if you have square matrices of same size):

A = round(rand(10,10)*10-5);
B = round(rand(10,10)*20-10);
for i = 1:size(A, 1)
  for j = 1:size(A, 2)
      AB{i, j} = A(i, j) * B;
  end
end
AB = cell2mat(AB);
disp(AB)

Good luck!

[Wei Hern]

the answer is given in sections. i would like my answer to be in one whole matrix. sorry..

any other methods to get the answer in one full matrix

[sixwwwwww]

Try this code:

A = round(rand(3)*10-5);
B = round(rand(3)*20-10);
for i = 1:size(A, 1)
  for j = 1:size(A, 2)
      AB{i, j} = A(i, j) * B;
  end
end
AB = cell2mat(AB);
disp(AB)

and its answer is a 9x9 matrix which is a full matrix. Did you try it? AB is the full matrix

[Wei Hern]

yes it works now! and I'm guessing that when i change the first value of the matrix, it would also be able to calculate no matter what the size of the matrix is? thanks heaps!

[sixwwwwww]

you are welcome. you can accept this answer if it is helpful to you